-121v^2+81=0

Solution for -121v^2+81=0 equation:

-121v^2+81=0

a = -121; b = 0; c = +81;
Δ = b2-4ac
Δ = 02-4·(-121)·81
Δ = 39204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{39204}=198$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-198}{2*-121}=\frac{-198}{-242}
=9/11
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+198}{2*-121}=\frac{198}{-242}
=-9/11
$